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Verizon [17]
3 years ago
13

60 POINTS TO QUICKEST AND CORRECT ANSWER!

Mathematics
2 answers:
kotykmax [81]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

Since the are the same equation they are already equal

Irina-Kira [14]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

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HELP ASAP GIVING BRAINLIST!!!!!!!!!!!!!
Vera_Pavlovna [14]

Answer:

x for the first one is equal to-4

4 0
2 years ago
A new skateboard cost $150. You have a 30% off coupon how much money did you save with your coupon?
insens350 [35]
150 x .30 = 45

You saved $45 if you use the coupon for the skateboard
5 0
3 years ago
On two investments totaling $11,500, Peter lost 3% on one and earned 4% on the other. If his net annual receipts were $⁢201, how
BlackZzzverrR [31]
Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
0.07Y = 546
Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
$201 = $201
6 0
3 years ago
If the bottom of a ship is 15.8 below the surface of the sea, calculate the pressure at the bottom of the ship. The density of t
Zolol [24]
Given:
Depth, h= 15.8
Density of seawater= 1030kg/m3

We need to find:
Pressure

Answer:
P= ρhg
P=(1030)(15.8)(9.81)= 159647.94 Pa
7 0
3 years ago
How would the factor pairs change if nancy had only 5 posters to arrange?
Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0
2 years ago
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