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Alisiya [41]
3 years ago
5

What is the area of the regular pentagon below?

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

<em><u>2</u></em><em><u>1</u></em><em><u>y</u></em><em><u>d</u></em><em><u>^</u></em><em><u>2</u></em>

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

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Your answer is -0.51923077
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3 years ago
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The diagram shows the width and area of a rectangle.
Mademuasel [1]

Answer:

The answer can be explained here: theraleighregister.com/the-diagram-shows-the-width-and-area-of-a-rectangl.html

Step-by-step explanation:

8 0
3 years ago
Which expression finds the measure of an angle that is coterminal with a 45° angle? 45° 90° 45° 180° 45° 270° 45° 360°.
agasfer [191]

The measure of an angle is the coterminal angle with a 45A°+360A° and can be determined by using the measurement of coterminal angles.

<h2>We have to determine</h2>

Which expression finds the measure of an angle that is coterminal with a 45° angle?

<h3>According to the question,</h3>

Coterminal angles are those angles that share the terminal side of an angle occupying the standard position.

The standard position means that one side of the angle is fixed along the positive x-axis, and the vertex is located at the origin.

<h3>A coterminal with 45° is 45°+k°360° with k as an integer.</h3>

Then,

The coterminal angle with 45°,

When k = 0

Then,

\rm = 45+(0)360\\\\= 45+0\\\\= 45 \ degree

When k = 1

Then,

\rm = 45+(1)360\\\\= 45+360\\\\= 405 \ degree

When k = -1

Then,

\rm = 45+(-1)360\\\\= 45-360\\\\= -315 \ degree

Hence, The measure of an angle that is coterminal with a 45A°+360A°.

For more details about the Coterminal angle refer to the link given below.

brainly.com/question/12378421

4 0
2 years ago
The closed form sum of
zalisa [80]

Perhaps you know that

S_2 = \displaystyle\sum_{k=1}^n k^2 = \frac{n(n+1)(2n+1)}6

and

S_3 = \displaystyle\sum_{k=1}^n k^3 = \frac{n^2(n+1)^2}4

Then the problem is trivial, since

\displaystyle\sum_{k=1}^n k^2(k+1) = S_2 + S_3 \\\\ = \frac{2n(n+1)(2n+1)+3n^2(n+1)^2}{12} \\\\ = \frac{n(n+1)\big((2(2n+1)+3n(n+1)\big)}{12} \\\\ = \frac{n(n+1)\big(4n+2+3n^2+3n\big)}{12} \\\\ = \frac{n(n+1)(3n^2+7n+2)}{12} \\\\ = \frac{n(n+1)(3n+1)(n+2)}{12}

Then

12\bigg(1^2\cdot2+2^2\cdot3+3^2\cdot4+\cdots+n^2(n+1)\bigg) = n(n+1)(n+2)(3n+1)

so that <em>a</em> = 3 and <em>b</em> = 1.

4 0
3 years ago
Help me please the first answer gets the brainiest
SCORPION-xisa [38]
I took a screen shot to mark the dots I hope this helps

4 0
2 years ago
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