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Alisiya [41]
3 years ago
5

What is the area of the regular pentagon below?

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

<em><u>2</u></em><em><u>1</u></em><em><u>y</u></em><em><u>d</u></em><em><u>^</u></em><em><u>2</u></em>

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

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Step-by-step explanation:

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Step-by-step explanation:

This figure is composed of circles, squares, and semicircles. As you can see, the squares indicate that each semicircle should have ( 1 ) the same area, and ( 2 ) the same length ( circumference ). It would be easier to take the circumference of the figure first, as it is composed of arcs part of semicircles the same length.

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3 0
3 years ago
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