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BARSIC [14]
4 years ago
11

A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a cus

tomer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 17 new rackets at 59 PSI. Upon receiving the rackets, the customer measured the tension of each and calculated the following summary statistics: sample mean = 56, standard deviation = 2.4 PSI. in order to conduct the test the customer selected a significance level of a = .05. Interpret this value.
A. The probability of concluding that the true mean is less than 59 psi when in fact it is equal to 59 psi is only .05.

B. The probability of concluding that the true mean is less than 59 psi when in fact it is equal to 59 psi is only .05.

C. The smallest value of ? that you can use and still reject H0 is 0 .05.

D. There is a 5% chance that the sample will be biased
Mathematics
1 answer:
AlekseyPX4 years ago
6 0

Answer:

Step-by-step explanation:

Given that a  local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 17 new rackets at 59 PSI. Upon receiving the rackets, the customer measured the tension of each and calculated the following summary statistics: sample mean = 56, standard deviation = 2.4 PSI.

Whenever we select alpha as 5% = 0.05 this means that whenever p value got from hypothesis test is less than this we reject null hypothesis. Otherwise we accept null hypothesis

C. The smallest value of p value  that you can use and still reject H0 is 0 .05.

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A tile of a square is of side 30 cm. How many such tiles would be required to cover a floor of a square room of side 6m?
Fiesta28 [93]

Answer:

4 tiles

Step-by-step explanation:

Area of a square tile:

A = s²

A = (30)²

A = 900 cm

900 cm = 9 m

Area of the square room:

A = s²

A = (6)²

A = 36 m

36 ÷ 9 = 4

4 0
3 years ago
If you get the answer right then I’ll mark brainlist.
galina1969 [7]

Answer:

<em>y</em> = -2

<em>x</em> = -2

Step-by-step explanation:

Both <em>x </em>and <em>y </em>equal -2 in the table.

6 0
3 years ago
A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr
worty [1.4K]

Answer:  The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation:  Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8  and  n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.

Now, the probability of pulling three green marbles out with replacement is given by

P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0
3 years ago
A politician's support grew from 42% by 3 percentage points to 45%. What percent (relative) change is this? Round your answer to
gregori [183]

Answer:

7.1%

Step-by-step explanation:

The formula for percentage relative change =

[Final value - Initial value/Initial value] × 100

From the above question

Initial value = 42 %

Final value = 45%

= 45 - 42/ 42 × 100

= 3/42 × 100

= 7.1428571429 %

Therefore, approximately to the nearest tenth, the percentage relative change = 7.1%

7 0
4 years ago
Pls help me it is only one questionnnn:)
lesya692 [45]

Answer:

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7 0
3 years ago
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