write an addition equation. the equation must have a 1-, a2-, and a 3-digit added and use all of these digit. 662288000

(15.34) The level of nitrogen oxides (NOX) in the exhaust of cars of a particular model varies Normally with mean 0.21 g/mi and

MrMuchimi

Answer:

a level of significance of 0.01 = 1%

Step-by-step explanation:

given

Z = 0.0001

mean μ=0.21 g/mi

variate x= 0.21 + 0.03

standard deviation σ= 0.05 g/mi.

N = sample population 20 cars

z = (x −μ )/[σ /√N ]

Z = $\frac{x −μ}{\frac{σ}{√N} }$

Z = 0.03/ (0.05/√20) = 0.03/0.0111

Z = 2.63 +- 0.0001

Z= 2.6301 or 2.6299

checking the level of significance table from a statistical book gives

a level of significance of 0.01 = 1%

therefore the null hypothesis is accepted.

7 0

3 years ago

How much would it be worth in 5, 10, 20 years

pochemuha

Answer:

$675

$850

$1200

Step-by-step explanation:

Use formula for simple interest:

A = P (1+rt)

where

A = accrued amount (principal + interest) = what we want to find

P = Principal (initial) amount = Given as $500

r = rate of interest = Given as 7% = 0.07

t = time

For 5 years, t = 5

A = 500 [ 1 + 0.07(5) ] = $675

For 10 years, t = 10

A = 500 [ 1 + 0.07(10) ] = $850

For 20 years, t = 20

A = 500 [ 1 + 0.07(20) ] = $1200

8 0

3 years ago

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

A quadrilateral has three angles which measure 23.5 degrees, 99 degree, and 100.4 degrees. What is the measure of the fourth ang

Schach [20]

I think it would be 137.1, due to the total being 360. Just subtract.

3 0

3 years ago

Read 2 more answers

Find the arrival time if the plane took off at 8:35 A.M. and flew for 2 hr. 55 min. Include A.M. or P.M. in your answer.

FrozenT [24]

11:30 am. 8:35 + 2 hours = 10:35 + 5 mins = 10:40 + 50 mins = 11:30 am

3 0

3 years ago