Each pair has 2 socks so 19÷2= 9 with 1 remaining unmatched sock.
A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer:
3 1/3
Step-by-step explanation:
2 + (-2/3)² ÷ 1/3
2 + 4/9 ÷ 1/3
2 + 4/9 × 3/1
2 + 12/9 = 2 + 4/3 = 2 + 1 1/3
= 3 1/3
I found the correct image that accompanies this problem and edited it with my answers.. Pls. see attachment.
Based on the attachment, the correct statements are:
<span>1) DO,2 (x,y) = (2x, 2y)
2) Side Q'S' lies on a line with a slope of -1.
Q'(-6,6) S'(-2,2)
m = y1 - y2 / x1 - x2
m = 6 - 2 / -6 - (-2)
m = 4 / -4
m = -1
</span><span>5) The distance from Q' to the origin is twice the distance from Q to the origin.
</span>
