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Solnce55 [7]
3 years ago
6

Fill in the missing number to complete the linear equation that gives the rule for this table.

Mathematics
2 answers:
allsm [11]3 years ago
6 0

Answer:

y=x-5

Step-by-step explanation:

6-5=1

7-5=2

8-5=3

The rule is subtract 5

kogti [31]3 years ago
5 0

Answer:

Y=x-5

Step-by-step explanation:

In the table the rule is -5

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The answer is x equals 1
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Solve 3x2+7x+1=0 using the quadratic formula.
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Answer:

x=\frac{-7+-\sqrt{37} }{6}

Step-by-step explanation:

This (±) goes between the -7 and \sqrt{37}

3x^{2} +7x+1=0

ax^{2} +bx+c

-b ± \sqrt{b^2-4ac}/2a

-7 ± \sqrt{(7)^2-4(3)(1)}/2(3)

-7 ± \sqrt{49-12}/6

-7 ± \sqrt{37}/6

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Andre drives a bike for 4 hours covering 160 km. Find the distance covered by him in 7 hours.
swat32

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4 0
2 years ago
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The square root of a negative number, such as StartRoot negative 144 EndRoot, is undefined. Explain why the square root of –x, S
monitta

Part A

The reason why the (√(-x)) is not necessarily undefined, is because x is a placeholder, such that x can take on a negative value for which  (-x) is a positive number, therefore, √(-x) = √(+ve number) is a defined real number.

Part B

The domain is x ≤ 0

The range is f(x) ≥ 0

<h3>What is Real Number?</h3>

A real number is a value of a continuous quantity that can represent a distance along a line.

Here, The given and required information:

Given that √(-144) = Undefined, why is √(-x) not necessarily undefined

The given function, f(x) = √(-x)

Part A

The square root of a real number with a negative value is an imaginary number

The square root of a real number with a positive value or zero, is a real number

√(144) = ±12

A variable, x, is an input value of a function that is a quantity place holder in the function which is a function argument

The given function is f(x) = √(-x)

Where;

x = An argument of the function

When x ≤ 0, such that x is a negative real number or zero, we have;

x = R⁻ or 0

Therefore;

-x= -R⁻ or 0 = R⁺ or 0

-x = R⁺

From which we get;

f(-x)= √(-x) = √(R⁺) = Defined

f(-x) = √(R⁺) ≥ 0 The range of the function is f(x) ≥ 0

An example, when x = -16, we have;

-x = -(-16) = 16

√(-x) √(16) = 4 (Defined)

Part B;

Thee domain where the function is defined is where x = -R⁻,  x ≤ 0

The output of the function f(x) is defined which is the range = f(x) ≥ 0

Thus, the reason why the √(-x) is not  necessarily undefined, is because the value of x can represent a negative real number or zero.

Learn more about real numbers here;

brainly.com/question/17201233

#SPJ1

6 0
2 years ago
Help what's the answer to this??
True [87]

Answer:

AD

Step-by-step explanation:

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3 years ago
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