We need to find the surface area of the solid.
Since it's formed by cubes with edges of 1 meter, each square on the surface of the solid has an area equal to:

Thus, to find its surface area, we need to count the number of squares on its surface, and then multiply this number by 1 meter².
We can see that this solid has two equal latera surfaces (right and left). Each one of them has 17 squares.
Also, the number of squares on the horizontal surfaces is the same on the top and bottom of the solid. Each one of them has 10 squares.
And the vertical surfaces on the front and back of the solid have the same number of squares: 8 squares each.
Then, adding those quantities and multiplying the result by two, we find the total number of squares on the surface of the solid:

Therefore, the surface area of the solid is 70 m².
Answer:
H) 2
Step-by-step explanation:

=
[since 0 < x < (π/2) and
]
= (1 + 1)
= 2
We know that in general,
by
we mean the positive square root of x only.
the answer is 576 2 cm
Step-by-step explanation:
hope i helped
Answer:
236
Step-by-step explanation:
The interquartile range is the right edge of the box minus the left edge of the box
The right edge of the box is 301
The left edge of the box is 65
301 -65 =236
The interquartile range is 236
4 cm, because 2 times 5 times x equals 40, x=4