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3 years ago

Need help with this please

Mathematics

1 answer:

Julli [10]3 years ago

4 0

Answer:

arc UTR = 212°

Step-by-step explanation:

The measure of an arc is congruent to the central angle subtended by the arc, thus

arc UT = 90° , arc TS = 90° and arc SR = 32°

arc UTR = UT + TS + SR = 90° + 90° + 32° = 212°

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-20x - 7y= 29 10x + 3y = -11

muminat

Answer:

x=1

Step-by-step explanation:

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3 0

3 years ago

A comic-strip writer churns out a different number of comic strips each day. For 16 days, the writer logged the number of comic

Nimfa-mama [501]

First we need to graph the given values.

there are total 16 data so x-value can be taken as 1,2,3,...,16

given values will be assigned as y-values as shown in attached table.

Now we just graph those points to see the type of skew.

From graph we see that points are very close and almost in the shape of a line. Lines seems to be moving upward when going to the right side.

Hence correct answer will be "positive skew".

4 0

3 years ago

Please answer I will give 20 points!!!

Alenkasestr [34]

The answer is: y= –1/3x–5

8 0

3 years ago

The two-way table shows the distribution of gender to favorite film genre for the senior class at Mt. Rose High School.

Studentka2010 [4]

Answer:

The second statement is correct

Step-by-step explanation:

Hello!

The table shows the information of the favorite film genre of the students of the class regarding their gender.

You have to prove which statement is correct:

1)The probability of randomly selecting a student who has a favorite genre of drama and is also female is about 17 percent.

If you chose a student at random, you need to calculate the probability of its favorite genre being "Drama" (D) and the student being female (F), symbolically: P(D∩F)

To do so you have to divide the number of observed students that are female and like drama by the total number of students:

P(D∩F)= $\frac{24}{240}= \frac{1}{10} =0.10$

This means that the probability of choosing a student at random and it being a female that likes drama is 10%.

This statement is incorrect.

2) Event F for female and event D for drama are independent events.

Two events are independent when the occurrence of one of them doesn't affect the probability of occurrence of the other one.

So if F and D are independent then:

P(F)= P(F|D)

-or-

P(D)=P(D|F)

The probability of the event "Female" is equal to $P(F)= \frac{Total females in the class}{n} = \frac{144}{240} = \frac{3}{5}= 0.6$

The probability of the event "Drama" is:

$P(D)= \frac{Total students that like "Drama"}{n}= \frac{40}{240}= \frac{1}{6}= 0.166$

$P(F|D)= \frac{P(FnD)}{P(D)}= \frac{\frac{1}{10} }{\frac{1}{6} }= \frac{3}{5} = 0.6$

As you can see P(F)= 0.6 and P(F|D)= 0.6 so both events are independent.

This statement is correct.

3) The probability of randomly selecting a male student, given that his favorite genre is horror, is 16/40

This is a conditional probability, you already know that the student likes horror movies (H), and out of that group you want to know the probability of the student being male (M):

$P(M|H)= \frac{number of male students that like horror movies}{total students that like horror movies}= \frac{16}{38}= \frac{8}{19} = 0.42$

This statement is incorrect.

4) Event M for male and event A for action are independent events.

Same as the second statement, if the events "Male" and "Action" are independent then:

P(M)= P(M|A)

-or-

P(A)= P(A|M)

$P(M)= \frac{96}{240}= \frac{2}{5}= 0.4$

$P(A)= \frac{72}{240} =\frac{3}{10}= 0.3$

$P(AnM)= \frac{28}{240}= \frac{7}{60}= 0.11666$

$P(M|A)= \frac{P(MnA)}{P(A)}= \frac{\frac{7}{60} }{\frac{3}{10} } = \frac{7}{18}= 0.3888$

$P(M)= \frac{2}{5}$ and $P(M|A)= \frac{7}{18}$

P(M)≠ P(M|A) the events are not independent.

This statement is incorrect.

I hope this helps!

6 0

3 years ago

PLEASE HELP ME SOLVE THIS QUESTION ASAPPPPPPPPPPP

AveGali [126]

Answer:

Step-by-step explanation:

Volume of the pyramid :

$V=\dfrac{x^2*h}{3} =554.9\\\\x^2*h=554.9*3\\\\h=15.1\\\\x^2*15.1=554.9*3\\\\x^2=\dfrac{554.9*3}{15.1} \\\\x=\sqrt{\dfrac{1664,7}{15.1} } \\\\x=\sqrt{110,24503311258278145695364238411...} \\\\x=10,499763478887644993681148554978...\approx{10.50}$

8 0

3 years ago