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Sindrei [870]
3 years ago
9

Right now, I am spending a lot of time listening to the voice of a particularly compelling character: the young Merlin. In the e

nd, I finally heard the voice of Merlin thanks to a surprising source: the haunting, mysterious hooting of a great horned owl outside the window of my Colorado home. As I listened to that owl's resonant [echoing] call in the pre-dawn hours one morning, something about it gave me a whole new cadence [rhythm], a whole new sound. And then, a whole new voice.
In this paragraph, what is the author's explicit message about his inspiration for Merlin's voice?

He had difficulty finding Merlin's voice.
His inspiration was the owl outside his window.
His old ideas were not working for Merlin's voice.
He spent a lot of time thinking about Merlin's voice.
Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

it is B

Step-by-step explanation:

Took The Test And Got It Right

stiv31 [10]3 years ago
5 0

Answer:

his inspiration was the owl outside his window.

Step-by-step explanation:

You might be interested in
Vihaan finds that the roots of a quadratic equation that contains a difference of squares pattern is x = +-16. What is true abou
tigry1 [53]

The answer to the question, <u>What is true about the graph of the parabola described by the quadratic equation</u> is that the parabola crosses the x-axis at x = ±16.

Since the quadratic equation has roots x = ±16, it implies that its factors are x - 16 and x + 16.

So, the quadratic equation is y = (x - 16)(x + 16) = x² - 16²

Also, we know that the roots of a quadratic equation are the points where the value of the quadratic equation equals zero. At this value, the quadratic equations crosses the x-axis at the roots of the quadratic equation.

Since the roots of our quadratic equation are x = ±16, it implies that the parabola crosses the x-axis at x = ±16.

So, the answer to the question, <u>What is true about the graph of the parabola described by the quadratic equation</u> is that the parabola crosses the x-axis at x = ±16.

Learn more about quadratic equations here:

brainly.com/question/18162688

5 0
3 years ago
Find the max/min value of f(x) = 2x2 + 3x - 5
Lelechka [254]

Answer:

The minimum value is (-\frac{3}{4},-\frac{49}{8}) or  (-0.75,-6.125)

Step-by-step explanation:

we have

f(x)=2x^{2}+3x-5

This is the equation a vertical parabola open upward

The vertex represent a minimum

The general equation in vertex form is

f(x)=a(x-h)^2+k

where

(h,k) is the vertex

Convert the given function in vertex form

f(x)=2x^{2}+3x-5

Factor 2

f(x)=2(x^{2}+\frac{3}{2}x)-5

Complete the square

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}

Rewrite as perfect squares

f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20n-%5Cfrac%7B1%7D%7B6%7D%20%3D-%5Cfrac%7B1%7D%7B3%7D%20%2B%5Cfrac%7B11
mel-nik [20]

Answer:

n = -2

Step-by-step explanation:

\frac{-5}{6}n-\frac{1}{6}=\frac{-1}{3}+\frac{11}{6}\\\\\frac{-5}{6}n=\frac{-1}{3}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{(-1)*2}{3*2}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2}{6}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2+11+1}{6}\\\\\frac{-5}{6}n=\frac{10}{6}\\\\n=\frac{10}{6}*\frac{6}{-5}\\\\n= -2

4 0
3 years ago
Need help will give you the brainliest
makkiz [27]
18 mi

To find the area of the sides do length times width so
4x1
and 1x1
There are four of the 4x1
and two or the 1x1
so 4x4=16 and 1x2=2
16+2=18
6 0
3 years ago
(05.03)
Dmitry [639]

Answer:

someone help pls

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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