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nadezda [96]
3 years ago
14

What is the value of x ?????

Mathematics
2 answers:
Rasek [7]3 years ago
3 0

what............there’s no pic

nexus9112 [7]3 years ago
3 0
X is an unknown value you can only know the value of x if it is used in an equation that you can solve

Hope this helps
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What can be the next step please helppppppppppppp
stepladder [879]

Answer:

Statement: Triangle ACD is congruent to Triangle BCD

Reason: SSA (Side, Side, Angle)

8 0
2 years ago
Find all solutions in the interval [0, 2π). tan x + sec x = 1
svp [43]
Use the identity 
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x  = 1 + tan^2x - 2 tan x
0 = -2 tanx 

tan x = 0 

x =  0, π 
π is an extraneous root because sec 180 = -1 
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6 0
3 years ago
Write a trinomial which is degree 2, where the coefficient of the highest degree term is 7.
Nady [450]

Answer:

7x^2 - 2x - 3.

Step-by-step explanation:

Starts with 7x^2  then a term in x then a constant.

4 0
2 years ago
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Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
2 years ago
Edward was running errands on his bike first to be like from his house to the post office to pick up a package the post office i
Karo-lina-s [1.5K]

Answer:

Edward drove altogether of 16.1 miles.

Step-by-step explanation:

Given:

Edward was Running around on his bike.

Distance from home to post office = 4 \frac{4}{5} \ miles

4 \frac{4}{5} \ miles can be Rewritten as 4.8 \ miles

Distance from home to post office = 4.8 \ miles

Now Given:

Distance from Post office to market = 3.25 miles.

Now we will calculate Distance from Home to market.

Distance from Home to market can be calculated by adding Distance from home to post office and Distance from Post office to market.

Framing in equation form we get;

Distance from Home to market = 4.8+3.25 = 8.05\ miles

Also Given:

his mother picked him up at the market and drove him home.

We need to find the total miles Edward drive altogether.

total miles Edward drive altogether will be equal to Sum of Distance from Home to market and Distance from market to home.

framing in equation form we get;

Total Distance Edward drove = 8.05+8.05 = 16.1\ miles

Hence Edward drove altogether of 16.1 miles.

5 0
2 years ago
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