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Mice21 [21]
4 years ago
11

Write an inequality to represent the graph

Mathematics
1 answer:
Elis [28]4 years ago
5 0

Answer:

its C. i hope this helps good luck and don't forget to thank and the brainly

Step-by-step explanation:

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How can i solve 9+21 as to factor the expression using the (GCF)
rosijanka [135]

The GCF is 9 because all the numbers are divisible by 9

9/9 = 1   and   21/9 = 3

now we are left with 1+3, but we don't get rid of the GCF

You have to put the GCF in front of your new expression

You should now have 9(1+3)

3 0
3 years ago
HELP ASAP <br><br> What is the value of x?
miskamm [114]

Answer:

47 degrees

Step-by-step explanation:

This is a parallel line, and this sort of angle is known as an alternate angle, which is a z shaped angle (can be a Z either way). Alternate angles are equal, therefore x=47 degrees too. Hope this helps :)

4 0
3 years ago
What is the value of the digit 6 in this number? Write your answer in number form.
dimulka [17.4K]

Answer:

one hundred million (100,000,000)

Step-by-step explanation:

600,000,000

3 0
3 years ago
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Ol) simplify 3x- 4b - 2a + 56 ​
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Answer:

in the image above

Step-by-step explanation:

------------------------------

4 0
3 years ago
Para el día del amigo, Juana tiene 24 caramelos de naranja, 36 de limón y 30 de uva. Si quiere armar la mayor cantidad de bolsas
antoniya [11.8K]

Answer:

a) Se requieren 6 bolsas para distribuir los caramelos, b) 4 caramelos de naranja, esta debe incluir 5 caramelos de uva y 6 caramelos de limón.

Step-by-step explanation:

a) Primero, se determina las razones de caramelos de limón y de uva por cada caramelo de naranja, pues los últimos son los artículos de menor cantidad.

Caramelos de limón por caramelo de naranja

x = \frac{36\,c.limon}{24\,c.naranja}

x = \frac{3}{2}

Se requieren 3 caramelos de limón por cada 2 caramelos de naranja.

Caramelos de uva por caramelo de naranja

y = \frac{30\,c.uva}{24\,c.naranja}

y = \frac{5}{4}

Se requieren 5 caramelos de uva por cada 4 caramelos de naranja.

Entonces, el nùmero de bolsas queda determinado por el máximo de caramelos por bolsa. Entonces, el número de bolsas es:

n = \frac{24\,c.naranja}{4\,\frac{c.naranja}{bolsa} }

n = 6\,bolsas

Se requieren 6 bolsas para distribuir los caramelos.

b) Puesto que cada bolsa tiene 4 caramelos de naranja, esta debe incluir 5 caramelos de uva y 6 caramelos de limón.

4 0
4 years ago
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