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4 years ago

Blank thousands = 1800 tens

Mathematics

2 answers:

Alexxx [7]4 years ago

6 0

the answer is: 18 thousands = 1800

arsen [322]4 years ago

3 0

18 thousands=1800 because if you do multiply 1800 ten times it would equal 18thosands

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Find the area between the graph of the given function and the x-axis over the given interval, if possible.

icang [17]

Answer:

Not possible to find out area

Step-by-step explanation:

Given is an exponential function as

$f(x) =e^{-x}$ and we have to find the area to the left of e above x axis under the curve.

Using integrals, we find area =

$\int\limits^e_{-\infty} e^{-x} \, dx\\=-e^{-x}$

substitute limits

When we substitute -infinity we get e^infty which is again infinity

Hence finding out area is not possible.

The integral of area diverges.

7 0

4 years ago

lewis has a net spendable income of $2,000 per month. He sets up the following transportation budget for himself.

Nataliya [291]

What’s the question?

8 0

3 years ago

PLEASE: Find The Ending Balence

eimsori [14]

Using exponential functions, the ending balances are given as follows:

1. $1,490.07.

2. $1,073.83.

3. $358.04.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

$A(t) = A(0)(1 + r)^t$

In which:

A(0) is the initial value.

r is the growth rate, as a decimal.

Item a:

The parameters are:

A(0) = 939, r = 0.08, t = 6.

Hence the balance is:

$A(6) = 939(1.08)^6 = 1490.07$

Item b:

The parameters are:

A(0) = 823, r = 0.03, t = 9.

Hence the balance is:

$A(9) = 823(1.03)^9 = 1073.83$

Item c:

The parameters are:

A(0) = 269, r = 0.1, t = 3.

Hence the balance is:

$A(9) = 269(1.1)^3 = 358.04$

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

4 0

2 years ago

Read 2 more answers

Find <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}" alt="a_{1}" align="absmiddle" class="latex-form

yKpoI14uk [10]

Answer:

$\displaystyle a_{1} = 108$

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

recall geometric sequence

$\displaystyle S_{ \text{n}} = \frac{ a_{1}(1 - {r}^{n} )}{1 - r}$

we are given that

$S_n=189$
$r=\dfrac{1}{2}$
$n=3$

thus substitute:

$\displaystyle 189= \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{1 - \frac{1}{2} }$

to figure out $a_1$ we need to figure out the equation

simplify denominator:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2} } = 189$

simplify square:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2} } = 189$

simplify substraction:

$\displaystyle \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2} } = 189$

simplify complex fraction:

$\displaystyle a_{1} (\frac{7}{8} ) \div { \frac{1}{2} } = 189$

calculate reciprocal:

$\displaystyle a_{1} \frac{7}{8} \times 2 = 189$

reduce fraction:

$\displaystyle a_{1} \frac{7}{4} \ = 189$

multiply both sides by 4/7:

$\displaystyle a_{1} \frac{7}{4} \times \frac{4}{7} \ = 189 \times \frac{4}{7}$

reduce fraction:

$\displaystyle a_{1} = 27\times 4$

simplify multiplication:

$\displaystyle a_{1} = 108$

hence,

$\displaystyle a_{1} = 108$

4 0

3 years ago

An artist created a statue in the shape of a triangular pyramid. The triangular base has a height of 9 feet and base of 16ft. De

MatroZZZ [7]

The volume is 240ft^3. v=Ah/3. v=(72)(10)/3. v=720/3. v=240.

6 0

3 years ago