Answer:
a: 0.08, or 8% chance he wins all 3
b: 0.42, or 42% chance he wins 2
Step-by-step explanation:
P(win A) = 0.8
P(lose A) = 0.2
P(win B) = 0.5
P(lose B) = 0.5
P(win C) = 0.2
P(lose C) = 0.8
The situations are independent, so we multiply probabilities together.
To win all 3: P(win A)*P(win B)*P(win C) = 0.8*0.5*.02 = 0.08
To win 2 of the 3 there are 3 ways to do this. We add up the probabilities of the 3 situations...
P(win A)*P(win B)*(lose C) = 0.8*0.5*0.8 = 0.32
P(win A)*P(lose B)*P(win C) = 0.8*0.5*0.2 = 0.08
P(lose A)*P(win B)*P(win C) = 0.2*0.5*.02 = 0.02
0.32 + 0.08 + 0.02 = 0.42
First, find the difference between each number in the sequence.... 34 - 25 = 9. 25 - 16 = 9 and 16 - 7 = 9... So, there is a constant difference of 9 between each number of the sequence. To find the 30th term, you could expand the sequence out to 30 (which is a good way to check your answer, but tedious)... So, simply add the 1st value of the sequence to the difference and multiply by 30 to find your 30th value.... 7 + 9 x 30 = 16 x 30 = 480.
Therefore, the 30th term is 480.
25%=25 candies
100 divided by 25=4
25*4=100 candies
100%=100 candies
Answer:
x^2(x-4) + 3(x-4)
(x^2 + 3)(x-4)
Step-by-step explanation:
