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lukranit [14]
3 years ago
5

HELP ASAPPPPPPPPPPP!!!

Mathematics
1 answer:
jekas [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Since its isosceles right triangle, then 2 sides are going to be the same. There are 2 legs that are in any triangle, they give us 1 leg so now we know what the other leg is. Now the formula for finding hypotenuse is a2+b2=c2.

3^{2}+3x^{2} =c^{2}     3 squared is 9, so 9+9=18

now we have c but we arent done so now we find the square root, \sqrt{18}. Which is 3\sqrt{2} or 4.24.

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Slav-nsk [51]
Give more detail please this makes zero sense
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What is the reference angle for the angle with measure −π4?
tresset_1 [31]

Answer:

D -7π4

Step-by-step explanation:

Just took the test my dude :D

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VMariaS [17]

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Step-by-step explanation:

6b+8=-4

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6b=-4-8

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2 years ago
Find the inverse of the function. f(x) = the cube root of quantity x divided by seven. - 9
elena-14-01-66 [18.8K]
To solve

replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

so
I'm not sure if it is
f(x)=\sqrt[3]{\frac{x}{7}}-9 or
f(x)=\sqrt[3]{\frac{x}{7}-9}


first one
f(x)=\sqrt[3]{\frac{x}{7}}-9
replace f(x) with y
y=\sqrt[3]{\frac{x}{7}}-9
switch x and y
x=\sqrt[3]{\frac{y}{7}}-9
solve for y
x+9=\sqrt[3]{\frac{y}{7}}
(x+9)^3=\frac{y}{7}
7(x+9)^3=y
replace y  with f⁻¹(x)
f^{-1}(x)=7(x+9)^3

2nd one
f(x)=\sqrt[3]{\frac{x}{7}-9}
replce f(x) with y
y=\sqrt[3]{\frac{x}{7}-9}
switch x and y
x=\sqrt[3]{\frac{y}{7}-9}
solve for y
x^3=\frac{y}{7}-9
x^3+9=\frac{y}{7}
7(x^3+9)=y
replace y  with f⁻¹(x)
f^{-1}(x)=7(x^3+9)



if you meant f(x)=\sqrt[3]{\frac{x}{7}}-9  then the inverse is f^{-1}(x)=7(x+9)^3

if you meant f(x)=\sqrt[3]{\frac{x}{7}-9}  then the inverse is f^{-1}(x)=7(x^3+9)

7 0
3 years ago
A Square has a perimeter of 28 feet. What is it's area?
rusak2 [61]

Answer:

784

Step-by-step explanation:

Use long multiplication to evaluate.

8 0
3 years ago
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