In quadrilateral abcd the measures of the angles are represented by measure angle a=6x-2, measure angle b=6x+5, measure angle c=
2 answers:
You might be interested in
Well, we know the line is perpendicular to that one above.... what is the slope of that one anyway? well, notice, the equation is already in slope-intercept form 
.
so, we're looking for the equation of a line perpendicular to that one, now, since that one has a slope of 4/3, a perpendicular line will have a negative reciprocal slope to that one,
so, what is the equation of a line whose slope is -3/4 and runs through -4,9?
![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ -4 &,& 9~) \end{array} \\\\\\ % slope = m slope = m\implies -\cfrac{3}{4} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-9=-\cfrac{3}{4}[x-(-4)] \\\\\\ y-9=-\cfrac{3}{4}(x+4)](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%26%26%28~%20-4%20%26%2C%26%209~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%20-%5Ccfrac%7B3%7D%7B4%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-9%3D-%5Ccfrac%7B3%7D%7B4%7D%5Bx-%28-4%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-9%3D-%5Ccfrac%7B3%7D%7B4%7D%28x%2B4%29)
now, the x-intercept for any function is found by zeroing out the "y" and solving for "x", thus
x = 8, y = 0 ( 8 , 0 )
so, we're looking for the equation of a line perpendicular to that one, now, since that one has a slope of 4/3, a perpendicular line will have a negative reciprocal slope to that one,
so, what is the equation of a line whose slope is -3/4 and runs through -4,9?
now, the x-intercept for any function is found by zeroing out the "y" and solving for "x", thus
x = 8, y = 0 ( 8 , 0 )
