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Alecsey [184]
4 years ago
7

Two players, A and B, alternately and independently flip a coin and the firstplayer to obtain a head wins. Assume player A flips

first.1. If the coin is fair, what is the probability that A wins?2. Suppose that P(head) = p, not necessarily 12. What is the probability that A wins?
Mathematics
1 answer:
mart [117]4 years ago
7 0

Answer:

Probability that A wins is 2/3.

Step-by-step explanation:

player A can win in 2 ways

1) Player A wins immediately by getting head

2) Player A loses immediately by getting tail but wins ultimately as player B gets losses.

a) Probability of 1 to happen is 1/2.

b) Similarly for the event 2 to happen the condition is that A get's a tail and B losses.

Let probability that A wins is 'p' thus we have

p=P(1)+P(2)\\\\p=\frac{1}{2}+\frac{1}{2}\times (1-p)\\\\

Solving for 'p' we get

p= 2/3.

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Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
What is the y-intercept of the line given by the equation y= 3x + 4?
DIA [1.3K]

Answer:

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Step-by-step explanation:

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James reads that 1 out of 6 eggs contains salmonella bacteria. So he never uses more than 5 eggs in cooking. If eggs do or don't
Dmitrij [34]

Answer:

B. binomial with n = 5 and p = 1/6

Step-by-step explanation:

Given that James reads that 1 out of 6 eggs contains salmonella bacteria.

So he never uses more than 5 eggs in cooking.

If eggs do or don't contain salmonella independently of each other, then

probability for any one egg to contain salmonella bacteria is the constant 1/6.

Also there are only two outcomes, either bacteria present or not.

Hence the  number of contaminated eggs when James uses 5 chosen at random has the distribution is Binomial

Here n = no of trials = no of eggs he uses = 5

Probability = 1/6

So option B is right.

3 0
4 years ago
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