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Contact [7]
3 years ago
14

Write a program to generate personalized junk mail. The program takes input both from an input file and from the keyboard.The in

put file contains the text of a letter, except that the name of the recipient is indicated by the three characters #N#. The program asks the user for a name and then writes the letter to a second file but with the three letters #N# replaces by the name. The three-letter string #N# will occur multiple times in the letter. Only the first name of the recipient is required You can ask the user to input the file name, or hard code the file name. you should write a function that reads from the file contains the body and writes to junk mail file
Computers and Technology
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

#include <iostream>

#include <fstream>

using namespace std;

void replace(ifstream&,ofstream&);

int main()

{char filename[30];

bool found=false;

cout<<"what is the name of the input file youare using? ";

cin>>filename;

ifstream input;

ofstream output;

input.open(filename);    

if(input.fail())

{ cout<<"file did notopen please check it\n";

system("pause");

return 1;

}

cout<<"what is the name of theoutput file you are using? ";

cin>>filename;

cin.ignore(100,'\n');

output.open(filename);

replace(input,output);

 

input.close();

output.close();

system("pause");

return 0;

}

void replace(ifstream& in,ofstream& out)    

{bool found=false;

string lookfor="#N#";

string data,name;

int n;

getline(in,data);

while(in)

{if(!found)

{n=data.find(lookfor,0);

if(n!=-1)

{found=true;

cout<<"Enter name: ";

getline(cin,name);

data.replace(n,3,name);

}    

}

out<<data<<endlu;

getline(in,data);

}

}

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Answer:

The answer is "Option ".

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circular_prime A number is called a circular prime if all rotations of its digits form a prime. For example, the number 197 is a
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Answer:

function out=circular_primes(no)

prim=primes(no);% find the all prime number till the given number

pr=0;

nos=[];

po=[];

for p=1:length(prim)

   n=prim(p); % picking up each prime no one by one

   n=num2str(n);% change into string for rotation of no

   d=length(n); % length of string

   if d>1          % take nos greater than 10 beacuase below 10 no need for rotation

       for h=1:d

           a=n(1);

           for r=1:d % for rotation right to left

               if r==d  5 % for the last element of string

                   n(d)=a;

               else

               n(r)=n(r+1); %shifting

               end

           end

           

       s=str2num(n); % string to number

       nos=[nos,s]; % store rotated elements in array

       end

       if nos(end)==no   %if given no is also a circular prime we need smaller

           break;

       end

       for gr=1:length(nos) % checking rotated nos are prime or not

           p1=isprime(nos(gr));

           po=[po,p1];    %storing logical result in array

       end

           if sum(po(:))==length(nos) %if all are prime the length and sum are must be equal

               

               pr=pr+1;

               out=pr;

           else

               out=pr;

           end

       po=[];

       nos=[];

   else  

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       f=isprime(s);

       if f==1

           pr=pr+1;

           out=pr;

       else

           out=pr;

       end

   end

       

      end

end

Explanation:

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