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Goshia [24]
3 years ago
6

Find csc x if sin x + cot x cos x =√3.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

Answer:

The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

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Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

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<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

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