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amm1812
3 years ago
6

The ages of three siblings combined is 27. The oldest is twice the age of the youngest. The middle child is 3 years older than t

he youngest.
Mathematics
2 answers:
kondaur [170]3 years ago
7 0

Answer:

the oldest sibling is 12 years old.

The middle child is 9 years old.

The youngest child is 6 years old.

Step-by-step explanation:

Let the age of the youngest child be x

Then the oldest child will be 2x.

The middle child will be x + 3.

Since the combined age is 27;

x + 2x + x + 3 = 27

4x = 27 - 3

x = 24 / 4

x = 6

now 2x = 12 and x + 3 = 9

leonid [27]3 years ago
3 0

Answer:

oldest is 12

middle is 9

youngest is 6

all add up to 27

Step-by-step explanation

idk if i did this right but i did 27 -3 =24

then i divide 24 by 2 which is twelve (the oldest's age)

then 12 divided by 2 is 6 which is the age of the youngest one

6 + 3 is 9, which is the age of the middle one.

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Answer:

The amount available in account at last is $0  

Step-by-step explanation:

Given as :

The withdrawal amount from the account at the end = $105

The first deposit amount = $45

The next three deposit amount = $20 each

I.e The second deposit amount = 3 × $20

Or, The second deposit amount = $60

Let The amount available in account at last = $A

<u>Now, According to question</u>

The amount available in account at last = (first deposit amount  + second deposit amount) - withdrawal amount from the account at the end

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3 years ago
What is the solution to<br> a&gt;-16?
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Answer:

that is the solution

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8 0
4 years ago
Please help I’ll mark brainliest, it looks like it’s not the whole thing but it is.
Dovator [93]

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Step-by-step explanation:

3 0
3 years ago
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ANSWER: M(-9,-4) to M’(-5,2)
If (x,y) is to (x+4,y+6)
Then (-9,-4) is to (-9+4,-4+6)
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4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=789%20%5Ctimes%20%20%7B8%7D%5E%7B2%7D%20%20%3D%20" id="TexFormula1" title="789 \times {8}^{2}
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Answer:

50496

Explanation:

789 × 8 × 8 = 50496

------------------------------------------------------------------------------------

<em>Hope it helps, if you have any question, comment down below!</em>

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