9514 1404 393
Answer:
117°
Step-by-step explanation:
We assume you want to report your bearing as an angle measured CW from North. For conventional angles greater than 90°, it will be ...
450° -angle = 450° -333° = 117°
The bearing of the ship is 117°.
Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.

We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.

Hence, the required temperature of the gas is 421.4 K.
-6, -4, -1, 3, 7
Hope this helps!
Combine like terms
-7y² + 6y² - 2y² = -3y²
4y + (-5y) - (-9y) = 4y - 5y + 9y = 8y
9 + 9 - (-2) = 9 + 9 + 2 = 20
-3y² + 8y + 20 is your answer
hope this helps