9x+13=2x+48
-2x -2x
7x+13=48
-13 -13
7x=35
/7 /7
x=5
y=9(5)+13
y=45+13
y=58
Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Answer:
0.55555555555555555555555555556
<em>(The 5 is repeating, so I rounded the last digit to 6.)</em>
Step-by-step explanation:
Divide 5/9. You get 0.5555... and the 5 is repeating.
Answer:
D
Step-by-step explanation:
Negative numbers are less than zero.