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DanielleElmas [232]
3 years ago
9

Who is this you tuber

Mathematics
2 answers:
wel3 years ago
4 0

Answer:

TheOdd1sOut

Step-by-step explanation:

:o

kupik [55]3 years ago
3 0

Answer:

theodd1sout pretty cool guy

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⦁ Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long a
lara [203]

Answer:

u can be using it at perpendicular and place it's center on point A

hope that helps a bit-

5 0
3 years ago
Needing help solving this question. Not sure on how to start the problem to solve it.
VashaNatasha [74]
Divide -3 from both sides leaving you with just m

make sure you switch the inequality sign
3 0
3 years ago
Nick bought a new car.
ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

A(t) = A(0)(0.88)^t.

It halves in value at t years, for which A(t) = 0.5A(0), hence:

A(t) = A(0)(0.88)^t

0.5A(0) = A(0)(0.88)^t

(0.88)^t = 0.5

\log{(0.88)^t} = \log{0.5}

t\log{0.88} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.88}}

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

9 0
1 year ago
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
What is universal gravitational constant
koban [17]

Answer:

6.67408 × 10^-11 m^3 kg^-1 s^-2

Step-by-step explanation:

F = G M 1 M 2 d 2 , where F is the gravitational force between two point masses, M1 and M2; d is the distance between M1 and M2; G is the universal gravitational constant, usually taken as 6.670 × 1011 m3/(kg)(s2) or 6.670 × 10−8 in centimeter–gram–second units. a = F M 1 = G M 2 r 2 .

8 0
3 years ago
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