Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
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Answer: D
-2.9a+6.8+4.4a-7.3
[-2.9a+4.4a]=1.5a
[6.8-7.3]=-0.5
1.5a-0.5
Remember you can do anyting to an equation as long as ou do it to both sides
-6x+4=-50
minus 4 both sides
-6x=-54
divide both sides by -6
x=9
5x+6=-44
minus 6 both sides
5x=-50
divide both sides by 5
x=-10
-3(7+6x)=-201
normally you would distribute (that works) but it's easier to divide both sides by -3
7+6x=67
minus 7 both sides
6x=60
divide by 6 both sides
x=10
Step-by-step explanation:
I am not critically certain but the ways you have jotted down your enquiry..
<h2>I assume is</h2>
13 × (4×11)
13 × 44
=572 - 44= 528
528+13 =541
541 ×13=7033
Answer:
(Choice C) 24+12R ≤100
$56
Step-by-step explanation:
Sofia ordered sushi for a company meeting. They change plans and increase how many people will be at the meeting, so they need at least 100 pieces of sushi in total. Sofia had already ordered and paid for 24 pieces of sushi, so she needs to order additional sushi. The sushi comes in rolls, and each roll contains 12 pieces and costs $8 Let R represent the number of additional rolls that Sofia orders.
1)
Which inequality describes this scenario?
Choose 1 answer:
(Choice A) 12+ 24R ≤ 100
(Choice B) 12+24R ≥ 100
(Choice C) 24+12R ≤100
(Choice D) 24+12 ≥100
2)
What is the least amount of additional money Sofia can spend to get the sushi they need?
ans) ___ dollars
please solve fast !!!! thank you from advance :)
The sushi comes in rolls, and each roll contains 12 pieces and costs $8 Let R represent the number of additional rolls that Sofia orders
Sofia has ordered 24 pieces
Sofia needs 100 pieces
sushi comes in rolls
12 pieces per roll
= 12R
24 + 12R ≤ 100
(Choice C) 24+12R ≤100
B.
24 + 12R ≤ 100
12R ≤ 100 - 24
12R ≤ 76
R ≤ 76 / 12
R ≤ 6.33
Approximately 7 rolls
Sofia will order 7 more rolls
Each roll cost $8
R ≤ 7
7 × 8
= $56
