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Sever21 [200]
3 years ago
11

PLEASE HELP ME this is really hard please

Mathematics
1 answer:
krok68 [10]3 years ago
7 0

Answer:

  1100

  2200

Step-by-step explanation:

Since speed is constant, the distance is proportional to the time. We notice that the number in the second column is 1650/3 = 550 times the number in the first column, so the two missing numbers are ...

  2 × 550 = 1100

  4 × 550 = 2200

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Step-by-step explanation:

3 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim
pogonyaev

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36  

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by \alpha=1-0.80=0.20 and \alpha/2 =0.10. And the critical value would be given by:

z_{\alpha/2}=\pm 1.28

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

Since we don't have prior info for the proportion of interest we can use \hat p=0.5 as estimator. And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36  

And rounded up we have that n=656

5 0
3 years ago
Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte
Tpy6a [65]

Answer:

3\frac{13}{20}=3.65 kg.

Step-by-step explanation:        

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are 2\frac{1}{4} kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add 2\frac{1}{4} and 1\frac{2}{5}  :

S= 2\frac{1}{4}+1\frac{2}{5}      

Upon converting our given mixed fractions into improper fraction we will get,

S= \frac{9}{4}+\frac{7}{5}

Now let us have a common denominator.

S=\frac{9*5}{4*5}+\frac{7*4}{5*4}

S=\frac{45}{20}+\frac{28}{20}

S=\frac{45+28}{20}

S=\frac{73}{20}  

S=3\frac{13}{20}  

S=3.65

Therefore, Sheldon picked 3\frac{13}{20}=3.65 kg of strawberries in the afternoon.  

3 0
3 years ago
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