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oee [108]
3 years ago
8

Evaluate −x^2−5 y^3 when x = 4 and y = 1

Mathematics
2 answers:
Natali [406]3 years ago
4 0

Answer:

Simplify:

-4^2-5(1^3)

So you get:

-21\\

Papessa [141]3 years ago
4 0

Answer:

\huge\boxed{-21}

Step-by-step explanation:

-x²-5y³

Given that x = 4, y = 1

-(4)^2-5(1)^3

-16-5(1)\\-16-5\\-21

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