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oee [108]
3 years ago
8

Evaluate −x^2−5 y^3 when x = 4 and y = 1

Mathematics
2 answers:
Natali [406]3 years ago
4 0

Answer:

Simplify:

-4^2-5(1^3)

So you get:

-21\\

Papessa [141]3 years ago
4 0

Answer:

\huge\boxed{-21}

Step-by-step explanation:

-x²-5y³

Given that x = 4, y = 1

-(4)^2-5(1)^3

-16-5(1)\\-16-5\\-21

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Cuánto dinero me gasto en colocarle baldosas a una sala comedor que tiene 9.30 de largo por 4.20 metros de ancho
Svetlanka [38]

La pregunta está incompleta ya que no se da el costo de la colocación de baldosas por m².

Suponga que el costo de los mosaicos por m² = c

Respuesta:

39.06c

Explicación paso a paso:

El costo del embaldosado será:

El costo por m² * área total a embaldosar

Dado que :

La dimensión de la habitación a embaldosar es:

Longitud = 9,30 metros

Ancho = 4.20 metros

El área total de la habitación a embaldosar es = Largo * ancho

Área total de la habitación a embaldosar = 9,30 m * 4,20 m

Superficie total de la habitación a embaldosar = 39,06 m²

Si el costo del mosaico por m² = c

El costo de embaldosar la habitación será:

39,06 * c = 39,06c

4 0
3 years ago
A cereal manufacturer packages breakfast cereal in individual - sized boxes measuring 2 inches by 3 inches by 4 inches. The same
Ilia_Sergeevich [38]

Answer:

2.5

Step-by-step explanation:


3 0
3 years ago
A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches
harkovskaia [24]

9514 1404 393

Answer:

  a) w(4w-15)

  b) w²

  c) w(4w -15) = w²

  d) w = 5

  e) 5 by 5

Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

__

b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

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c) Equating the expressions for area, we have ...

  w(4w -15) = w²

__

d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

__

e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

4 0
3 years ago
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natita [175]

Answer:

do it yourself kid.

Step-by-step explanation:

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