Ask question

Ask question

All categories

2 years ago

9

island rentals charges a $50 base fee plus $25 per hour to rent an electric boat that can carry six people . Thomas and his frie

nds put their money together and rent an electric boat for a day . For how many hours can they rent the boat if they have $225 ?

2 answers:

12345 [234]2 years ago

6 0

They can rent the boat for 7 hours if u add 50+25×7 it equals $225.

Alexus [3.1K]2 years ago

5 0

They can rent it for 7 hours

You might be interested in

Solve for y, show your steps<br><br><br>y = x(2y - 3)

Xelga [282]

Answer:

y= $\frac{-3x}{-2x+1}$

Step-by-step explanation:

3 0

2 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

<em><u>Substitute eqn 2 in eqn 1</u></em>

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

<em><u>Solve by quadratic equation</u></em>

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

2 years ago

Please help I will give brainliest.

Kay [80]

(2,0) and (-1/2,0) is the correct answer

3 0

1 year ago

Read 2 more answers

Please look at screen shot

Mnenie [13.5K]

Answer:

Quick Clean..........

3 0

2 years ago

A high school drama club is putting on their annual theater production. There is a maximum of 800 tickets for the show. The cost

astra-53 [7]

<span>a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.</span>

3 0

2 years ago