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Neporo4naja [7]
3 years ago
10

What is the surface area of this cube? The circled answer 16mm is incorrect. Please see attachment.

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0

its 96

the area of each square is 4x4 and theres 6 squares. (4x4)6

Crazy boy [7]3 years ago
5 0

Answer: LAST OPTION

Step-by-step explanation:

To  solve this problem you must:

- Calculate the surface area of one of the squares, with the formula for calculate the surface area of a square, where "s" is the lenght of any side of the square, then you obtain;

A=s^{2}=(4mm)^{2}=16mm^{2}

- Now, you must multiply this area by 6 (6 faces of the cube), then the results is:

SA=16mm^{2}*6=96mm^{2}

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BigorU [14]
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Answer: B. 
8 0
3 years ago
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Shtirlitz [24]
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Now add the two area's together:

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4 0
3 years ago
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

y=3(x+5)^2-75+71

So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

now, we can compare and find h and k

y=3(x+5)^2-4

we get

h=-5

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so, extreme value of this equation is

(h,k)=(-5,-4)

6 0
4 years ago
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What is the answer for (-3)+4x +2+2x +2x
sineoko [7]

Answer:

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8 0
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