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yarga [219]
3 years ago
14

Pls help!will give brainliest!

Mathematics
1 answer:
Cloud [144]3 years ago
7 0

Answer:

itb is j

Step-by-step explanation:

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Which would be included in a probability model for rolling a cube with faces numbered 1 through 6. Select all that apply.
Inessa [10]

Answer:

it's b.

Step-by-step explanation:

3 0
3 years ago
A cone is formed from a 300-degree sector of a circle of radius 18 by aligning the two straight sides. what is the result when t
vampirchik [111]

The radius of the completed cone is

... 18×(300°/360°) = 15

The height of the completed cone is found from the Pythagorean theorem:

... 15² + h² = 18²

... h = √99 = 3√11

The volume is given by

... V = (1/3)πr²·h = (1/3)π·15²·3√11

Dividing this value by π gives 225√11 cubic units.

7 0
3 years ago
Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
Add or subtract the polynomials<br> (8x3+3x-2)+(9x2-7+3x-2x3)
crimeas [40]

Answer:

10x^3+9x^2-9

Step-by-step explanation:

8x^3+2x-2+9x^2-7+2x-2x^3 - Combine like terms

10x^3+9x^2-9

4 0
3 years ago
Read 2 more answers
What would be the answer
sashaice [31]

Answer:

I think It's option (B) 45

Step-by-step explanation:

But I am not sure It's correct or not

I hope It's helpful

6 0
3 years ago
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