Hi my name is nadia so i felt like answering this lol. this question is missing a lot of things. it doesn’t look like i can answer it.
Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have

Let A represents area, and area is the product of length and width .
So we get

Substituting the value of y, we will get

Second part
The area is maximum at the vertex, and vertex is

And

And that's the required dimensions .
Answer:
Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Middle 68%
Between the 50 - (68/2) = 16th percentile and the 50 + (68/2) = 84th percentile.
16th percentile:
X when Z has a pvalue of 0.16. So X when Z = -0.995
84th percentile:
X when Z has a pvalue of 0.84. So X when Z = 0.995.
Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve
X/58.65 = 15/100
(58.65*15)/100 = tip
Answer: 3/5
Step-by-step explanation: Using the place value chart, we can see that the decimal 0.6 is 6 tenths. So we can write 0.6 as the fraction 6/10.
Notice however that 6/10 is not in lowest terms.
So we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.
So if we divide the numerator and denominator by 2, we get 3/5.
So 0.6 can be written as the fraction 3/5 which is in lowest terms.
Image provided showing the place value chart.