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4 years ago

Tom shoveled 12.5 yards of sand in 2.5 hours. At that rate how many yards did he shovel in one hour?

1 answer:

8 0

$\bf \begin{array}{ccll}
yards&hours\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
12.5&2.5\\
y&1
\end{array}\implies \cfrac{12.5}{y}=\cfrac{2.5}{1}\implies \cfrac{12.5\cdot 1}{2.5}=y$

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3 years ago

Answer all questions CORRECTLY BIG POINTS!

hammer [34]

y^2+9y+20
y^2+10y+21
y^2+2y+3
Step-by-step explanation:

(y+5(y+4) =y(y+4)+5(y+4) =y^2+4y+5y+20 =y^2+9y+20
(y+3(y+7) =y(y+7)+3(y+7) =y^2+7y+3y+21 =y^2+10y+21
(y+3)(y-1)

=y(y-1)+3(y-1)

=y^2-y+3y-3

= y^2+2y+3

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3 years ago

Read 2 more answers

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andre [41]

P=12

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3 years ago

Read 2 more answers

what is the value of x? SHOW ALL YOUR WORK. ONLY ANSWER IF YOU KNOW. PLEASE DONT REWRITE SOMEONE ELSE'S ANSWER DOWN. WILL MARK B

ioda

Answer:

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Step-by-step explanation:

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3 years ago

Please help me compute standard deviation! Here is the problem, as written.

aleksandr82 [10.1K]

Answer:

The standard deviation for the income of super shoppers is 76.12.

Step-by-step explanation:

The formula to compute the standard deviation for the grouped data probability distribution is:

$\sigma=\sqrt{\sum [(x-\mu)^{2}\cdot P(x)]}$

Here,

<em>x</em> = midpoints

$\mu=\sum x\cdot P(x)$

Consider the Excel table attached below.

The mean is:

$\mu=\sum x\cdot P(x)=32.3$

Compute the standard deviation as follows:

$\sigma=\sqrt{\sum [(x-\mu)^{2}\cdot P(x)]}$

$=\sqrt{259.71}\\\\=76.1155204\\\\\approx 76.12$

Thus, the standard deviation for the income of super shoppers is 76.12.

3 0

3 years ago