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ss7ja [257]
4 years ago
12

70 POINTS SHOW WORK

Mathematics
2 answers:
lord [1]4 years ago
8 0
Area of triangle = 1/2 x base x height

so old triangle we have  1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
 so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches
Firdavs [7]4 years ago
6 0
Assuming that the base can be 2 in and the height can 48. changing the lengths to a base of 6 and a height of 24 the triangle's area is 72 or times the original area by the increase over the decrease ... 3/2
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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
Rajesh Jorge 3/4 miles and then Walker 1/6 miles yo cool down. How far did he travel
scoundrel [369]

Answer:

I DONTBKNOW BUT FAR LOL

8 0
4 years ago
Find the value of Y! please help
Maurinko [17]

Answer:

y = 5.6

Step-by-step explanation:

Use Sine

Sine = \frac{opposite}{hypothenuse}

Sine 45 = \frac{y}{18}

Sine of 18 is 0.309

0.309 = \frac{y}{18}

Multiply 18 on both sides

0.309 x 18 = \frac{y}{18} x 18

5.562 = y

Round to the nearest tenth:

5.562 = 5.6

3 0
3 years ago
The sum of two numbers is at most 12, and the sum of 3 times the first number and 8 times the second number is at least 48 selec
Sever21 [200]

Answer:

(4,8)

Step-by-step explanation:

4 + 8 = 12

3(4) + 8(8)

= 12 + 64

= 76

6 0
3 years ago
The sum of two numbers is 33.the larger number is 3 more than two times the smaller number.what are the numbers?
e-lub [12.9K]

Answer: The numbers are 10 and 23

Step-by-step explanation:

Let the smaller number be x

And the larger number be y

Ist sentence;

1. The sum of two numbers is 33.

X + y= 33 .........eqn 1

2. second sentence

the larger number is 3 more than two times the smaller number.

Y = 3 +2x

Put y into eqn 1

X+ 3 +2x = 33

3x= 33- 3

3x= 30

X = 30/3

X= 10 and y= 3+ 2x

Y= 3+ 2(10)

Y = 3+ 20

Y= 23

Therefore the two numbers are 10 and 23

8 0
4 years ago
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