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3 years ago

70 POINTS SHOW WORK

2 answers:

8 0

Area of triangle = 1/2 x base x height

so old triangle we have 1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches

Firdavs [7]3 years ago

6 0

Assuming that the base can be 2 in and the height can 48. changing the lengths to a base of 6 and a height of 24 the triangle's area is 72 or times the original area by the increase over the decrease ... 3/2

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sp2606 [1]

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viktelen [127]

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2 years ago

Read 2 more answers

The equation of a circle is ( x - 3) 2 + ( y + 2) 2 = 25. The point (8, -2) is on the circle.

Shtirlitz [24]

Answer:

x =8 is the equation of the tangent.

Step-by-step explanation:

Here the equation of the given circle is: $(x-3)^{2} + (y+2)^{2} = 25$

Now, comparing it with the general equation of circle: $(x-h)^{2} + (y -k)^{2} = r^2$

we get the central coordinates (h,k) = (3,-2)

So, the slope of the line joining center and (8, -2) = $\frac{-2 -(-2)}{8-3} = \frac{0}{5} = 0$

Since the slope of line = 0, line is parallel to x axis.

Now, as tangent and the line is perpendicular to each other

⇒Slope of the tangent = -1/ slope of the line = $\frac{-1}{0}$

Now, by point slope formula: the equation of the tangent is

(y-y0) = m (x-x0)

or, $(y +2) = \frac{-1}{0} (x -8)$

or x =8 is the equation of the tangent.

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D

strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$

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2 years ago