3 years ago

Solve 60 = 10√ y – 3

Mathematics

1 answer:

Kay [80]3 years ago

6 0

60 = 10 * sqrt (y) -3

add 3 to each side

63 = 10 sqrt(y)

divide by 10

63/10 = sqrt y

6.3 = sqrt (y)

square each side

(6.3)^2 = y

39.69 = y

Answer: y=39.69

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3. Given that ∆RSV - ∆RTU, find the coordinates of S and the scale factor. R(0, 0) T(16,0) V(0, --6) U(0, -8)

MArishka [77]

Answer:

I'll give the scale factor and you can compute the coordinates of S

Step-by-step explanation:

the dilation if centered about the origin is the scale factor multiplied by each coordinate.

so looking at points V and U, the scale factor F is found by solving for F:

-6xF= -8

F=8/6=4/3

Now you can compute the coordinates for S

send a comment if you need help

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2 years ago

What is 17,683 rounded to the nearest ten thousand?

MrMuchimi

20,000

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3 years ago

Read 2 more answers

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$