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OverLord2011 [107]
3 years ago
14

Solve 60 = 10√ y – 3

Mathematics
1 answer:
Kay [80]3 years ago
6 0

60 = 10 * sqrt (y) -3

add 3 to each side

63 = 10 sqrt(y)

divide by 10

63/10 = sqrt y

6.3 = sqrt (y)

square each side

(6.3)^2 = y

39.69 = y

Answer: y=39.69

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15 − b × d ÷ c<br><br><br> for b = 1, c = 6, and d = 18.
nirvana33 [79]

Answer:

This is simple. And, you best not be cheating either.

15 - 1 x 18 / 6

1x18 = 18

18/6 is 3.

15 - 3 = 12

12 is the answer.

Step-by-step explanation:

6 0
4 years ago
Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the
Arte-miy333 [17]

This question is incomplete, the complete question is;

Determine if the described set is a subspace. Assume a, b, and c are real numbers.

The subset of R³ consisting of vectors of the form \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0

  • The set is a subspace
  • The set is not a subspace

Answer:

Therefore; The set is not a subspace

Step-by-step explanation:

Given the data the question;

the subset R³;

S = {  \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0 }

we know that a subset of R³ is a subspace if it stratifies the following properties;

  1. it contains additive identity
  2. it is closed under addition
  3. it is closed under scales multiplication

Looking at the properties, we can say that it is not a subspace

As;

         u = \left[\begin{array}{ccc}1\\1\\0\end{array}\right] ∈ S       and v = \left[\begin{array}{ccc}0\\1\\1\end{array}\right]  ∈ S

As    1×1×0=0                          0×1×1=0

But   u+v = \left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] = \left[\begin{array}{ccc}1\\2\\1\end{array}\right]  ∉  S     as 1×2×1 ≠ 0

Hence, it is not closed under addition.

Therefore; The set is not a subspace

4 0
3 years ago
Correct answer will get brainliest
marshall27 [118]

Answer:

7) -3

8) B

Step-by-step explanation:

4 0
3 years ago
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Vikentia [17]
The answer is 3Е38, 30,000,000,000,000,000,000,000,000,000,000,000,000
7 0
4 years ago
How far from the base of the house do you need to place a 15' ladder so that its exactly reaches the top of a 12' wall?
salantis [7]
Sketching the ladder and wall might help to make the question clearer.  The ladder is represented by the hypotenuse of a right triangle and is opposite the 90-degree angle of this triangle.  The opposite side of this triangle measures 12 feet.  Thus, you have 2 of 3 sides in a right triangle:  a 12-foot opposite side and a 15-foot hypotenuse.  Can you now find the measure of the adjacent side, which is the distance the base of the ladder is located away from the base of the wall?  The Pythagorean Theorem would be the easiest approach to use here, but you could also solve this problem using trig. 
6 0
3 years ago
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