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Airida [17]
4 years ago
10

What is the volume of 2 moles of methane (CH4)? (One mole of any gas occupies 22.4 L under certain conditions of temperature and

pressure. Assume those conditions for this question.)
a. 44.8 L
b. 22.4 L
c. 20 L
d. 2.0L
Chemistry
1 answer:
Tju [1.3M]4 years ago
8 0

Answer:

2 moles of Methane gas will occupy 44.8 L

Explanation:

If one mole of any gas occupies 22.4 L under certain conditions of temperature and pressure, and those conditions are assumed in this question, then we comfortably solve this problem as follows;

1 mole of Methane gas ---------------> 22.4 L

2 moles of Methane gas -------------->?

Cross and multiply, 2 moles of Methane gas = 2 X 22.4 L = 44.8L

Therefore, 2 moles of Methane gas will occupy 44.8 L, if the conditions of temperature and pressure are maintained.

OPTION A IS THE RIGHT SOLUTION.

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Which combination of atmospheric conditions created this weather over the Golden Gate Bridge in San Francisco?
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Answer:

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How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the
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The balanced chemical reaction is:

<span>Ca + Cl2 =  CaCl2
</span>
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A19.0g sample of brass, which has a specific heat capacity of 0.375·J*g^−1°C−, is dropped into an insulated container containing
djverab [1.8K]

Answer:

The final temperature is 20.3 °C

Explanation:

Considering that:-

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Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{brass}\times C_{brass}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{brass}\times C_{brass}\times (T_i-T_f)

For water:

Mass = 300.0 g

Initial temperature = 20.0 °C

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Initial temperature = 81.7 °C

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So,  

300.0\times 4.184\times (T_f-20.0)=19.0\times 0.375\times (81.7-T_f)

1255.2T_f-25104=582.1125-7.125T_f

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