Answer: Jimmy Neutron 's House is host to Jimmy Neutron, Judy Neutron, Hugh Neutron, and Goddard. It is located on one side of the street from Cindy Vortex 's Building, both of which are located in Retroville, Texas, the United States of America, Alaska and Hawaii, North America and Planet Earth. Inhabitant: Jimmy Neutron.
Explanation:
160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
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Answer:-
7.03 g
Explanation:-
Let the mass of water needed be M.
So total mass = M + 0.37
Now 5% of this solution has 0.37g of rubidium chlorude.
∴ (M +0.37) x (5/100) = 0.37
M +0.37 = 0.37 x 100/5
M + 0.37 = 7.4
M = 7.4-0.37
=7.03
Thus water to be added is 7.03 gram
