Answer:
a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³
Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³
B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³
Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³
Explanation:
Using the ideal gas equation:
PV = nRT
Further explanations are found in the attachment below.
Answer:
29.9 g of CO₂ will be produced by the reaction.
Explanation:
This is the reaction:
CaCO₃(s) + 2HCl (aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
First of all, we state the moles of each reactant:
68.1 g . 1mol/ 100.08g = 0.680 mol of carbonate
51.6 g . 1 mol/36.45g = 1.46 mol of acid.
The solid salt is the limiting reactant. Ratio is 2:1
2 moles of acid can react to 1 mol of salt
1.46 mol of acid may react with (1.46 . 1)/2 = 0.727 moles
As we only have 0.680 moles of salt, we do not have enough.
Let's work at the product side. Ratio is 1:1
1 mo of salt can produce 1 mol of gas
0.680 moles will produce 0.680 moles of gas
We convert the moles to mass → 0.680 mol . 44g / 1mol = 29.9 g of CO₂
Answer:
Compound state
Explanation:
Because reactive elements mostly react immediately with other elements
Answer:
C₆H₆
Explanation:
We need to find the molecular formula of a compound of carbon (C) and hydrogen (H), so what <em>we need to find out is the number of atoms of C and of H in the molecule.</em> We know:
- molar mass = 78.1 g/mol
- C% = 92.3% = 92.3 g C / 100 g compound
So, in 1 mol of compound, 92.3% of the mass corresponds to Carbon:
<u>mass of C / mol of compound</u> = molar mass × C% = 78.1 g/mol × 92.3/100 = <u>72.1 g/mol</u>
<u>moles of C</u> = mass C / molar mass C = 72.1 g / 12.011 g/mol
moles of C = 6 moles of C per mol of compound
If 72.1 g in a mol of compound are Carbon atoms, the difference between the molar mass and the mass of Carbon atoms will correspond to H atoms in 1 mol of compound:
<u>mass of H / mol of compound</u> = molar mass - mass of C/mol
mass of H = 78.1 g / mol - 72.1 g /mol = <u>6.0 g/mol of compound</u>
<u>moles of H</u> = mass H / molar mass H = 6.0 g / 1.008 g/mol
moles of H = 6.0 moles of H per mol of compound
<em>So</em><em> one mol of compound has 6 moles of C and 6 moles of H.</em>
The molecular formula is then written as C₆H₆
Boiling point of cyclohexane at 620 mm hg?
Standard atmospheric pressure is 760 mm Hg. Boiling point at 760 mm= 80.74˚C
A liquid boils when its vapor pressure is equal to the atmospheric pressure. The vapor pressure of a liquid is proportional the absolute temperature of the liquid.
As the atmospheric pressure decreases, less vapor pressure is needed to cause the liquid to boil. Less vapor pressure means lower temperature.
The boiling point of cyclohexane at 620 mm Hg is less than 80.74˚C
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