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ziro4ka [17]
3 years ago
13

119 divided by 17? with remainder?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

A number, when divided by 119, leaves a remainder of 19. If it is divided by 17, it will leave a remainder of 2

Step-by-step explanation:

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Show all work to identify the asymptotes and zero of the function f of x equals 6 x over quantity x squared minus 36.
andrew11 [14]

Answer: Vertical asymptotes: x = -6,6

Horizontal asymptotes: y = 0

Step-by-step explanation: Not sure

7 0
2 years ago
HOW MANY AUTOMOBILE LICENSE PLATES CAN BE MADE IF EACH PLATE
ahrayia [7]

The number of license plates is 11232000

<h3>How to determine the number of license plates?</h3>

The given parameters are:

Characters = 6 i.e. 3 letters and 3 digits

Letters = 3 different letters

Digits = 3 different digits

There are 10 different digits and 26 different letters.

Since each character is different from the other, then we have:

Digits = 10, 9 and 8

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n = 10 * 9 * 8 * 26 * 25 * 24

Evaluate the product

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Hence, the number of license plates is 11232000

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1 year ago
How do I do orders of operations
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Step-by-step explanation:


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8 0
3 years ago
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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
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