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diamong [38]
3 years ago
5

Luna want to know what proportion of the 7th graders at her school are interested in taking art class. Which is the best group s

urvey to find this information.
A:ask all of her classmates in her homeroom who show up for school one day? B:ask every person who is waiting at her bus stop one afternoon. C:ask every 12th person who leaves school one afternoon. roll dice to determine which person to ask first. D: ask all her friends to ask their friends. PLEASE HELP ME!!
Mathematics
2 answers:
Temka [501]3 years ago
7 0
C. Ask every 12th person who leaves school one afternoon. Roll dice to determine which person to ask first.
pentagon [3]3 years ago
5 0

Answer:C ask every 12th person one day

Step-by-step explanation:

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If X = 6 cm and Y = 8 cm, what is the length of Z?
AleksAgata [21]
Use the trick x+ y+ z =0 and 6+8+z=0,...so z= -14
3 0
3 years ago
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

<em>Let p = </em><u><em>proportion of the students who are in favor of Mike.</em></u>

So, Null Hypothesis, H_0 : p \leq 50%      {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, H_A : p > 50%      {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students body in favor of Mike = \frac{55}{100} = 0.55

           n = sample of students taken = 100

So, <em><u>test statistics</u></em>  =   \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

                               =  1.01

The value of z test statistics is 1.01.

<em>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</em>

<em>Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0
3 years ago
A baker bakes 50 muffins. 1/5 of the muffins are chocolate chip. 1/2 of the muffins are blueberry. The rest are cinnamon. How ma
vitfil [10]

Answer:

15 muffins are cinnamon.

Step-by-step explanation:

Given that:

Number of muffins baked = 50 muffins

Chocolate chip muffins = 1/5 of 50 = \frac{1}{5}*50

Chocolate chip muffins = 10 muffins

Blueberry muffins = 1/2 of 50 = \frac{1}{2}*50

Blueberry muffins = 25

Cinnamon muffins = Muffins baked - chocolate chip muffins - blueberry muffins

Cinnamon muffins = 50 - 10 - 25

Cinnamon muffins = 50 - 35 = 15

Hence,

15 muffins are cinnamon.

5 0
3 years ago
Norton read 4 books during his vacation. the first book had 326 pages, the second had 288 pages,the third had 349 pages and the
Murrr4er [49]

The four books had an average of 341 pages

Step-by-step explanation:

Given

Total number of books = 4

Pages in first book = x1 = 326

Pages in second book = x2 = 288

Pages in third book = x3 = 349

Pages in fourth book = 401

The average is given by:

Average=\frac{Sum\ of\ pages}{number\ of\ books}\\=\frac{x_1+x_2+x_3+x_4}{4}\\=\frac{326+288+349+401}{4}\\=\frac{1364}{4}\\=341

The four books had an average of 341 pages

Keywords: Average, Division

Learn more about average at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

8 0
3 years ago
Need help with all them, state how you know also<br><br> Triangle Congruency
nata0808 [166]

Answer

where is the pdf?

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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