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zheka24 [161]
3 years ago
8

What is the solution to the equation 1/3 (x - 2) = 1/5 (x + 4) + 2?

Mathematics
2 answers:
allsm [11]3 years ago
6 0
The solution is x=26
VladimirAG [237]3 years ago
5 0

Answer:

The solution is x = 26

Step-by-step explanation:

Here, the given equation is,

\frac{1}{3}(x-2)=\frac{1}{5}(x+4)+2

Add fractions on right side,

\frac{1}{3}(x-2)=\frac{x+4+10}{5}

By cross multiplication,

5(x-2)=3(x+14)

By distributive property,

5x-10=3x+42

Adding 10 on both sides,

5x=3x+52

Subtract 3x on both sides,

2x=52

Divide both sides by 2,

x=26

Which is the required solution,

Last option is correct.

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Find the sum. <br> (- 7/2 z + 4) + (1/5 z - 15)<br> HELPPP
Nonamiya [84]

Answer:

-33/10z - 11

Step-by-step explanation:

since all of these terms are being added, there are no need for the parenthesis

-7/2z +4 + 1/5z -15

add like terms (to add the fractions, convert them to a common denominator)

-7/2z + 4 + 1/5z - 15

-35/10z + 2/10z - 11

-33/10z - 11

8 0
2 years ago
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
If f(x)=x^2-11x+18 what are the zeros of the function?
UkoKoshka [18]
X= 9 x=2
-2 × -9=18
-2 + -9= -11
8 0
2 years ago
What is the length of the strip of seaweed around the outside of the sushi?
SashulF [63]
To find the circumference of a round object, you will take the diameter and multiply is by pi to get 78.5mm

8 0
2 years ago
Assume that all triangles have interior angles less than 90°.A surveyor sights on a survey marker that is 132.3m distant. She ne
Vadim26 [7]

Answer:

  85.9 m

Step-by-step explanation:

The law of sines can help figure this.

The remaining angle in the triangle is ...

  180° -75° -68° = 37°

This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...

  b/sin(B) = c/sin(C)

  b = sin(B)·c/sin(C) = 132.3·sin(37°)/sin(68°) ≈ 85.873 . . . meters

The surveyor is about 85.9 meters from the second marker.

4 0
3 years ago
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