Question

How many grams of nitrogen and oxygen are required to make 85 grams to trinitrogen tetroxide?

Answer 1

mass of N₂ = 25.76 g

mass of O₂  = 58.88 g

Explanation:

Nitrogen (N₂) will react with oxygen (O₂) to form trinitrogen tetroxide (N₂O₄).

N₂ + 2 O₂ → N₂O₄

number of moles = mass / molecular weight

number of moles of N₂O₄ = 85 / 92 = 0.92 moles

Knowing the chemical reaction we devise the following reasoning:

if       1 moles of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄

then X moles of N₂ react with Y moles of O₂ to produce 0.92 moles of N₂O₄

X = (1 × 0.92) / 1 = 0.92 moles of N₂

Y = (2 × 0.92) / 1 = 1.84 moles of O₂

mass = number of moles × molecular weight

mass of N₂ = 0.92 × 28 = 25.76 g

mass of O₂  = 1.84 × 32 = 58.88 g

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