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BARSIC [14]
3 years ago
8

A solution has a hydrogen ion concentration of 0.001 M, what is the pH of the solution

Chemistry
1 answer:
LenKa [72]3 years ago
4 0
PH= −log
10
​
[H
+
]
= −log
10
​
(0.001)
= −log
10
​
(10
−3
)
= −(−3)log
10
​
10
pH=3.
01
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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
2 years ago
Water molecules are listed from A to B to C in
Sunny_sXe [5.5K]
The answer is b, least to greatest motion.

The higher the temperature a substance is, their particles have more kinetic energy and thus move faster and have a faster motion.

From the pictures, we can see that the state changes from the coldest, ice, to the least cold, water, and to the hottest, steam. Therefore, the hotter the substance it, the water molecules have a greater motion.

So your answer is b.
7 0
3 years ago
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How many molecules are there in a 1.43 mole sample of H2O2?
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One mole of hydrogen peroxide contains 6.02 x 10^23 molecules of hydrogen peroxide. And each molecule contains 4 atoms, so the answer is 4 x 6.02 x 10^23.
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Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.
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(P1V1/T1)=(P2V2/T2)

I just took the test and this should be correct

4 0
3 years ago
When ethyl acetoacetate (ch3coch2co2ch2ch3) is treated with one equivalent of ch3mgbr, a gas is evolved from the reaction mixtur
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The protons of methylene group between the two carbonyl groups in ethylacetoacetate are acidic in nature. When compounds containing such acidic protons are treated with bases the loose proton and form enolates.

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6 0
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