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ICE Princess25 [194]
4 years ago
12

An objects starting position is at a point A and it's final point in at B to figure out what the speed is in between what other

information should be needed
Chemistry
1 answer:
Nina [5.8K]4 years ago
3 0
More precisely, we need to specify its position<span> relative to a convenient reference frame. .... Also you s</span>hould know<span> that some people use the subscript "0" to refer to the ... mx, </span>start<span> subscript, 0, end subscript, equals, 1, </span>point<span>, 5, space, m and her </span>final<span> ... </span>between<span> two </span>points<span>, or we </span>can<span> talk about the distance traveled by an </span>object<span>.</span>
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What information is given by the superscripts in an electron configuration?
Paraphin [41]
<span>The superscripts in an electron configuration represents the number of electrons and protons in an element. </span>
8 0
3 years ago
On a number line, the number O would make a good...
AVprozaik [17]

Answer: Base point

Explanation: Base point

8 0
3 years ago
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Which missing item would complete this beta decay reaction?<br> PLATO
goldfiish [28.3K]

Answer: _{-1}^0\beta

Explanation:  

General representation of an element is given as:   _Z^A\textrm{X}

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Beta decay : In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The given reaction would be represented as:

_{43}^{98}\textrm{Tc}\rightarrow_{44}^{98}\textrm{Pb}+_{-1}^0\beta

7 0
3 years ago
Read 2 more answers
QUESTION 17
borishaifa [10]

Question 17:

False; cutting hair would change what it looks like but, braiding it keeps it the same substance it is.


Question 18 :

My best guess would either be A or D. I would lean more towards D because if there are different mixtures then it depends on what you are mixing.


Hope it helps in some way. <3

5 0
3 years ago
. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are
olga nikolaevna [1]

<u>Answer:</u> The standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

<u>Explanation:</u>

We are given:

K_{sp}\text{ of }Ag_2S=8\times 10^{-51}

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K = equilibrium constant or solubility product = 8\times 10^{-51}

Putting values in above equation, we get:

\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ

For the given chemical equation:

Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)

The equation used to calculate Gibbs free change is of a reaction is:  

\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]

The equation for the Gibbs free energy change of the above reaction is:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]

We are given:

\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ

Putting values in above equation, we get:

285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol

Hence, the standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

8 0
3 years ago
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