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3 years ago

A. Write a balanced chemical equation for this reaction below.

Chemistry

1 answer:

I am Lyosha [343]3 years ago

4 0

Answer:

Fe(s) + 3H2O2(aq) ................. FeO3(s) + 3H2O (l)

Explanation:

Fe(s) + H2O2(aq) ---------------- FeO3(s) + H2O (l)

To balance the equation put coefficient of 3 at back of H2O and H2O2

Fe(s) + 3H2O2(aq) ................. FeO3(s) + 3H2O (l)

To check, the number of atoms of each element on the left must be equal to that of the right.

Element Left. Right

Fe. 1 1

H. 3×2=6 2×3=6

O. 3×2 =6. 3+3 = 6

This shows that the equation is balanced

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In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

The reaction is the following:

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To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

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Where:

m: is the mass

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And for nitrogen:

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We can see in reaction (1) that 3 moles of hydrogen react with 1 mol of nitrogen, so the number of hydrogen moles needed to react nitrogen is:

$n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles$

Since we have 3.47 moles of hydrogen and we need 7.50 moles to react with all the mass of nitrogen, the limiting reactant is hydrogen.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that 3 moles of hydrogen produces 2 moles of ammonia, so:

$n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles$

Hence, hydrogen would produce 2.31 moles of ammonia.

Therefore, hydrogen is the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

Find more about limiting reactants here:

brainly.com/question/2948214?referrer=searchResults

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