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ziro4ka [17]
3 years ago
11

HNO3 + Mg(OH)2 yield Mg(NO3)2 + H2O​

Chemistry
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

yes

Explanation:

because this is a neutralization reaction that yield salt and water

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Advocard [28]

Answer:

D.

Explanation:

Decompostion of stone due to acid rain

8 0
3 years ago
Read 2 more answers
In the lewis structure of ch3oh, how many lone pairs of electrons are there? in the lewis structure of ch3oh, how many lone pair
Lunna [17]
The structure of Methanol (CH₃OH) is shown below. This structure contains 2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,

                        Oxygen  =  8  =  1s², 2s², 2px², 2py¹, 2pz¹

There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.

7 0
3 years ago
At a constant pressure and amount of gas, how are temperature and volume related?
RSB [31]
The volume is directly proportional to the absolute temperature so the answer is A.
7 0
3 years ago
Acetaldehyde (CH3CHO) undergoes a Wolf-Kishner reaction, which is the addition of hydrazine (H2NNH2) with subsequent addition of
Anarel [89]

Answer:

Reduced, alkane

Explanation:

Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.

This reaction occurs at high temperature.

Alkane formed has a same number of carbon as aldehyde and ketone.

If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.

Here, acetaldehyde is reduced to form ethane.

So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine  with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.

6 0
3 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

7 0
3 years ago
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