Answer:
1.20 × 10³ torr
Explanation:
Step 1: Given data
- Initial pressure (P₁): 822 torr
- Initial temperature (T₁): 325 K
- Final temperature (T₂): 475 K
Step 2: Calculate the final pressure of the gas
Considering the constant volume, if we assume the gas behaves ideally, we can calculate its final pressure using Gay-Lussac's law.
P₁/T₁ = P₂/T₂
P₂ = P₁ × T₂/T₁
P₂ = 822 torr × 475 K/325 K = 1.20 × 10³ torr
Mass of CO₂ produced : 58.67 g
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
CS₂ + 3O₂ -------> CO₂ + 2SO₂
mol of CO₂ based on mol of O₂ as a limiting reactant(CS₂ as an excess reactant)
From the equation, mol ratio of mol CO₂ : mol O₂ = 1 : 3, so mol CO₂ :
mass CO₂ (MW= 44 g/mol) :
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
Answer:
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution. Mathematically written as:
Moles of citric acid = n
Volume of the citric acid solution = 125 mL =125 × 0.001 L= 0.125 L
(1 mL = 0.001L)
Molarity of the citric acid solution = 0.400 M
n = 0.400 M × 0.125 L = 0.05 moles
Mass of 0.05 moles of citric acid :
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
A that’s the answer I’m not really 100% sure.