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3 years ago

3. * + 4y = 6 = -x +3 What is the answer

Mathematics

1 answer:

miv72 [106K]3 years ago

6 0

Answer:

the answers is -4

Step-by-step explanation:

-1+3 I think this the answer

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What is the missing justification?

Vikki [24]

Transitive property is your answer

if ∠A ≅ ∠C, and ∠C ≅ ∠B then, ∠A ≅ ∠B

hope this helps

4 0

2 years ago

Read 2 more answers

XD Plzzzzzz do 2 slides (4 problems)

Leya [2.2K]

Answer:

Slide 1:

1. Solution = (-3,2)

y = 2x - 1

y = 3/2x + 6

2. No solution

y = -4/2x + 4

y = -4/2x - 5

Slide 2:

3. Solution = (1, -6) ONE SOLUTION

4. Solution = (-4, -1) ONE SOLUTION

p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4

I really hope this helped :)

6 0

3 years ago

(3x3 - 7x2 + 12) - (3x3 + 6x2 + 10x)

inn [45]

(3x³ - 7x² + 12) - (3x³ + 6x² + 10x)
(3x³ - 3x³) + (-7x² + 6x²) - 10x + 12
-x² - 10x + 12

6 0

3 years ago

Read 2 more answers

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

2 years ago

Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items,

Ivanshal [37]

Answer:

77.64% probability that there will be 0 or 1 defects in a sample of 6.

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The true proportion of defects is 0.15

This means that $p = 0.15$

Sample of 6:

This means that $n = 6$

What is the probability that there will be 0 or 1 defects in a sample of 6?

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.15)^{0}.(0.85)^{6} = 0.3771$

$P(X = 1) = C_{6,1}.(0.15)^{1}.(0.85)^{5} = 0.3993$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3771 + 0.3993 = 0.7764$

77.64% probability that there will be 0 or 1 defects in a sample of 6.

5 0

2 years ago