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guajiro [1.7K]
2 years ago
14

A concreter has a 36kg bag of cement mix on the back of his ute .the bag broke and 1/10 was lost.How much cement mix was left in

the bag.?
Mathematics
1 answer:
katovenus [111]2 years ago
4 0

Answer:

<u>32.4 kg were left in the bag</u>

Step-by-step explanation:

1. Let's check the information provided for answering the question:

Weight of the bag of cement = 36 kg

Fraction of the cement bag lost = 1/10

2. How much cement mix was left in the bag?

For calculating how much cement was left, we use this equation:

x = Cement left in the bag

x = 36 - 1/10 * (36)

x = 36 - 36/10

10x = 360 - 36 (Multiplying by 10 at both sides)

10x = 324

<u>x = 32.4 kg</u>

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Answer:

2over/a -b-c

Step-by-step explanation:

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5 0
3 years ago
The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki
Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

t is the number of months since January.

Now, we use a cosine curve to model this scenario

Vertical shift will be;

D = ( 6 + 14 ) / 2 = 20 / 2

D = 10

Next is the Amplitude;

|A| = ( 6 - 14 ) / 2

|A| = 4

Now, the horizontal stretch factor will be;

B = 2π / 12

B = π/6

Hence;

S(t) = 4cos( π/6 × t ) + 10 ----------- let this be equation 1

Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

9 - 10 = 4cos( π/6 × (t-2) )

-1 = 4cos( π/6 × (t-2) )

-1/4 = cos( π/6 × (t-2) )

so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2)  -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

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2 years ago
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B
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3 years ago
What is the solution?
Cloud [144]
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8 0
3 years ago
Read 2 more answers
2) In a set of data that show a normal distribution the mean is 7.8 and the standard deviation is 1.7. What is the proportion of
abruzzese [7]
First, we get the z-score using formula:
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3 years ago
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