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Rudik [331]
3 years ago
9

Divide £60 in a ratio of 2:1

Mathematics
2 answers:
Fofino [41]3 years ago
7 0

Answer:

the division according to ratio is :

£40 and £20

Step-by-step explanation:

here's the solution: -

let the ratios be 2x and x

now, we know ;

=》2x + x = 60

=》3x = 60

=》x = 60 ÷ 3

=》x = 20

so, the the divisions will be :

=》2x = 2 × 20 = £40

=》x = £20

gavmur [86]3 years ago
3 0

£40 and £20

Step-by-step explanation:

let the parts be 2x and x (2:1)

2x+x=£60

or, 3x= £60

or, x= £20

2x=2×£20=£40

x=£20

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Answer:

a. 5 + x = -5 (Subtraction) 0.

b. -17 + x = 0 (Addition) 17.

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d. x + (-27) = 0 (Addition) 27.

e. x + (-30) = 0 (Addition) 30.

Step-by-step explanation:

In this exercise, students are required to match each equation with its solution. (The corresponding operations must be presented at the end of this point

a. 5 + x = -5 (Subtraction) 0.

x = -5 - 5

x = 0

b. -17 + x = 0 (Addition) 17.

x = 0 + 17

x = 17

c. 30 + x = 0 (Subtraction) -30.

x = 0 - 30

x = -30

d. x + (-27) = 0 (Addition) 27.

x - 27 = 0

x = 0 + 27

x = 27

e. x + (-30) = 0 (Addition) 30.

x - 30 = 0

x = 0 + 30

x = 30

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Step-by-step explanation:

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1 year ago
javier will paint the four outside walls of the birdhouse but not the bottom or the roof.What is the area that javier will paint
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What is the first term in a geometric sequence if the common ratio is − 2 and the sum of the first six terms is −105?
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\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
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r=-2\\
n=6\\
S_6=-105
\end{cases}

\bf -105=a_1\left( \cfrac{1-(-2)^6}{1-(-2)} \right)\implies -105=a_1\left( \cfrac{1-(64)}{1+2} \right)
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-105=a_1\left( \cfrac{-63}{3} \right)\implies -105=a_1(-21)
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3 years ago
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ 
(2) \ ln \  b^{a} = a*ln \ b \\
(3) \ ln \ a + ln \ b = ln \ (ab) \\
(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
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ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
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