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hjlf
4 years ago
13

Over which interval is the graph of the parent absolute value function f(x) = |xl decreasing?

Mathematics
2 answers:
Romashka [77]4 years ago
8 0

Answer:

(-∞,0)

Step-by-step explanation:

Graph y=|x|

Note that the graph is shaped like a V. The left half of the graph is decreasing from -∞ up until 0 when it hits the origin and starts to increase. Put this into interval notation: (-∞,0).

Elis [28]4 years ago
3 0

Answer:

(-infinity, 0)

Step-by-step explanation:

I did the test and got 100

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If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750​
maksim [4K]

Answer:

\boxed {\boxed {\sf 250 \ people}}

Step-by-step explanation:

Let's set up a proportion using the following setup.

\frac {buses}{people}=\frac {buses}{people}

We know 30 buses can carry 1,500 people.

\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}

\frac {30 }{1500 }=\frac {5 }{x }

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

30*x=1500*5\\30x=7500

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

30x/30=7500\\x=250

5 buses can carry 250 people.

7 0
3 years ago
John wants to invite around 78,000 college students to a tournament. Which of the following sets of college student populations
Ad libitum [116K]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
Kryger [21]

Answer:

a) P= $56,972.5

b) A=$1,26,792.3

Step-by-step explanation:

Given Data:

Interest rate=r= 0.08  per year

No. of years=t=10

Rate of continuous money flow is given by the function

f(t)=2000

a) to find the present value of money

P=\int\limits^n_0 {f(t)e^{-rt} } \, dt

Put f(t)=2000 and n=10 years and r=0.08

P=\int\limits^n_0 {2000e^{-0.08t} } \, dt

Now integrate

P= {2000(\frac{e^{-0.08t}}{-0.08} )

P= -\frac{2000}{0.08} (e^{-0.08*10}-e^{-0.08*0})

P= -\frac{2000}{0.08} (e^{-0.8}-e^{0})

P= -\frac{2000}{0.08} (0.4493-2.7282)

P= -\frac{2000}{0.08} (-2.2789)

P= -25000(-2.2789)

P= $56972.5

(b) to find the accumulated amount of money at t=10

A=P(e^{rt} )

Where P is the present worth already calculated in part a

A=56972.5(e^{0.08*10} )

A=56972.5(e^{0.8} )

A=56972.5(2.2255 )

A=$1,26,792.3

5 0
3 years ago
Find the point on the line y = 2x + 3 that is closest to the origin.
ch4aika [34]
1)We have to make a line perpendicular to y=2x+3, passing through the point (0,0).

y=2x+3   
m=solpe=2

The slope of the line perpedicular to y=2x+3 is m´
m´=-1/m
m´=-1/2

Point slope form:
y-y₀=m(x-x₀)
(0,0)
m=-1/2

y-0=-1/2(x-0)
y=-x/2

Therefore, the line perpendicular to y=2x+3 is y=-x/2.

2)The point on the line y=2x+3 tha is closest to the origin is the point of intersection of the two lines.

y=2x+3
y=-x/2

We can solve this system of equations by equalization method.
2x+3=-x/2
least common multiple=2
4x+6=-x
4x+x=-6
5x=-6
x=-6/5  (=-1.2)

y=-x/2
y=-(-6/5)/2=6/10=3/5    (=0,6)

Therefore: the point of the line y=2x+3 that is closest to the origin is:
 (-1.2 , 0.6)

3 0
3 years ago
Please help problem below 15 POINTS!!
solniwko [45]

i=\frac{12*1.9x^{x} }{x}

3 0
4 years ago
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