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sleet_krkn [62]
3 years ago
7

Write an equation of a line in slope intercept form with the given slope and the y-intercept.

Mathematics
1 answer:
defon3 years ago
7 0
The way you put it is confusing. I'll answer but the way you put it was confusing to me.
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. Isabella buys a 1.75 litre carton of apple juice. What is the largest number of 200 millilitre glasses that she can have from
Free_Kalibri [48]

Answer:

<em>The largest number of glasses of juice Isabella can have from the carton is 8.</em>

Step-by-step explanation:

<u>Ratios</u>

Knowing the total capacity of the carton of apple juice Ct, and the capacity of each glass Co, we can calculate how many glasses can be taken from the carton by finding the ratio:

\displaystyle n=\frac{Ct}{Co}

There are 1,000 milliliters in one liter, thus the carton has a capacity of

C t= 1.75*1,000 = 1,750 milliliters

Thus,

\displaystyle n=\frac{1,750}{200}

n=8.75

Since we cannot have 8.75 glasses, we round to the previous integer, then:

The largest number of glasses of juice Isabella can have from the carton is 8.

6 0
2 years ago
5/8 write a fraction or mixed number as a decimal
Citrus2011 [14]
.125 Iknow this as a fact ._.

4 0
3 years ago
Read 2 more answers
HELP!GIVING BRAINLIEST!!
s344n2d4d5 [400]

Answer:

2x+4

Step-by-step explanation:

3 0
3 years ago
PLEASE ANSWER THIS ASAP, I WILL BE GIVING YOU A THANKS! .
timama [110]

Answer:

D.) 12

Step-by-step explanation:

16x - 3(4x + 5) = 2x + 9

16x - 12x - 15 = 2x + 9

4x - 2x = 15 + 9

2x = 24

2x/2 = 24/2

x = 12

Check:

16x - 3(4x + 5) = 2x + 9

16(12) - 3(4(12) + 5) = 2(12) + 9

192 - 3(48 + 5) = 2(12) + 9

192 - 3(53) = 24 + 9

192 - 159 = 33

33 = 33

3 0
2 years ago
The t value for a 99% confidence interval estimation based upon a sample of size 10 is
Aliun [14]
Answer:
For a sample size of 10, the t-value is about 3.25 (from tables) at a 99% confidence interval.

Explanation:
When the standard deviation for the population is not known, the confidence interval estimate for the population mean is performed with the Student's t-distribution.
The confidence interval for the mean is calculated as
(\Bar{x}- t\frac{s}{\sqrt{n}} , \, \Bar{x}+ t\frac{s}{\sqrt{n}}
where
 \Bar{x} = sample mean,
s = sample standard deviation,
t = t-value (provided in tables),
n =  sample size.

When reading the t-value, (n-1) is called the df or degrees of freedom.

7 0
3 years ago
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