To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
3x + 11y = 4
2x + 6y = 0
I got
15/2, -5/4
5x - 18 + x = 90
6x = 108
x = 18 degrees
you could either multiply straight away or you could simplify right then so that you wouldn't have to it later.
20/5 * 5/2
your answer would be 10 either way
