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xz_007 [3.2K]
4 years ago
5

You work at a job where your average monthly earnings are $682 with a standard deviation of $49. Your mean monthly expenses are

S211 with a standard deviation of $16. Assume that the your monthly earnings and expenses are independent. You put any extra money that you have at the end of the month into your savings account. What is the mean of the amount of money you put in your savings account each month? Preview What is the standard deviation of the amount of money you put in your savings account each month?
Mathematics
1 answer:
Pavel [41]4 years ago
3 0

Answer:

S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

Step-by-step explanation:

Let I the random variable that represent the income for each month and we know:

E(I) = 682, \sigma_I = 49

Let E the random variable that represent the monthly expenses for each month and we know:

E(E)= 211, \sigma_E = 16

And for this case we know that the random variables I and E are independent, so then Cov(I, E) = 0

We can define the random variable S representing the amount that we can save each month and we can define S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

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Answer:

Step 1: Remove parentheses by multiplying factors.

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Step 2: Combine like terms by adding coefficients.

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VARVARA [1.3K]

a= 34 degrees

b= 28 degrees

c= 62 degrees

Step-by-step explanation:

First you know that b is 1/2 of 56 degrees or 28.

The triangle with the a in it is isoceles because the two sides are both radii.

In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.

Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.

We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.

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Sutract 5a -3b +2b from a-4b -2c​
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Step-by-step explanation:

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El triángulo ABC es equilátero y L, M y N son los puntos medios de BC, AB y CA respectivamente. Si MN = 3, ¿cuál es el valor de
Flauer [41]

The value of <u>ML = 3</u>, using the mid-point theorem of triangles.

According to the midpoint theorem, "the line segment of a triangle crossing the midpoints of two sides of the triangle is said to be parallel to its third side and also half the length of the third side."

In the question, we are given that triangle ABC is an equilateral triangle, and L, M, and N are the midpoints of BC, AB, and CA respectively.

Thus, by the midpoint theorem, we can say that:

  • MN || BC, and MN = (1/2)BC,
  • ML || AC, and ML = (1/2)AC, and
  • NL || AB, and NL = (1/2)AB.

Assuming AB = BC = AC = x units, we get:

  • MN = (1/2)BC = x/2,
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Thus, the triangle LMN is an equilateral triangle.

Thus, MN = ML = NL.

Given MN = 3, we can write the value of ML = 3.

Thus, the value of <u>ML = 3</u>, using the mid-point theorem of triangles.

Learn more about the mid-point theorem of triangle at

brainly.com/question/9635025

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The given question is in Spanish. The question in English is:

"Triangle ABC is equilateral and L, M, and N are the midpoints of BC, AB, and CA respectively. If MN = 3, what is the value of ML?"

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